What is the work done on a block as its radius decreases on a horizontal table?

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To determine the work done on the block as its radius decreases from 0.63 m to 0.51 m, it is essential to calculate the change in kinetic energy due to the increase in velocity. The initial speed is 1.5 m/s, and the final speed, after adjusting for the new radius while maintaining centripetal acceleration, is calculated to be 1.667 m/s. The work done can then be found by calculating the difference in kinetic energy between the two states. Since the centripetal acceleration remains constant, the force required to pull the string is minimal, simplifying the analysis. The key focus is on the change in kinetic energy to find the work done during this process.
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A small block of mass 0.91 kg slides without friction on a horizontal table. Initially it moves in a circle of radius r0 = 0.63 m with a speed 1.5 m/s. It is held in its path by a string that passes through a small hole at the center of the circle. The string is then pulled down a distance of r0 - r1 = 0.12 m, leaving it at a radius of r1 = 0.51 m. It is pulled so slowly that the object continues to move in a circle of continually decreasing radius.
How much work was done by the force to change the radius from 0.63 m to 0.51 m?

I need help with setting this one up. I don't know what to do. Thanks.
 
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The added force is incredibly small, so you can assume the centripetal acceleration is the same at the end as it was in the beginning. So calculate the new velocity based on that
 
So i get the final velocity as 1.667m/s, but I need acceleration to calculate work, and I don't have the time.
 
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