Shreya
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- Homework Statement
- Why does surface tension seems to have direction in these images? Isn't it a scalar?
- Relevant Equations
- S=Fl/Av
The Young-Laplace equation describes the relationship between surface tension and pressure differences across a curved surface. Surface tension, represented as a scalar ##\gamma(\mathbf{r})##, generates a force along a bounding contour ##\mathcal{C}##, calculated using the integral ##\displaystyle{\int}_{\mathcal{C}} \gamma(\mathbf{r}) \mathbf{n} ds##, where ##\mathbf{n}## is a unit vector. Young's law relates the three surface tensions involved in the equilibrium of different phases, specifically through the equation S(la)cos(θ) + S(sa) = S(sl). Understanding these concepts is crucial for analyzing forces at interfaces in fluid mechanics.
PREREQUISITESStudents and professionals in physics, fluid mechanics, and engineering who seek to deepen their understanding of surface phenomena and the mathematical relationships governing them.
ergospherical said:surface tension force exerted by one phase on the other is ∫Cγ(r)nds where n is a unit vector tangent to S but orthogonal to C.
Thank you erogospherical and haruspex! It makes sense now!haruspex said:illustrating forces arising from surface tension.
Can you explain what you mean by a contour?ergospherical said:containing a bounding contour
Thank you Chester, I get it now !Chestermiller said:to each arbitrary curve or line within the surface.
- the word contour, in that context, is just a fancy word for a curve :)Shreya said:Can you explain what you mean by a contour?
And what is Young's law ? (I haven't studied it yet)
S(la)cos (theta) + S(sa) = S(sl), right?ergospherical said:Young's law gives the relationship between the three surface tensions; what is it?
Posts #2 and #6 both mention that the force is in relation to a given line element within the surface, and acts orthogonally to it within the surface.Shreya said:Tangent to surface would mean 2 directions. So why do we consider a particular direction here. i e how do i know which one of the two to choose?
And it helps me to remember the units [force/length] in this context. The force "supplied" by the tension across that line element is proportional to the tension "times" the length of the small element.haruspex said:Posts #2 and #6 both mention that the force is in relation to a given line element within the surface, and acts orthogonally to it within the surface.
Thank you, hutchphd! I had actually learned this, but the textbook didn't mention the name.hutchphd said:Young -Laplace equation