What is this vector problem asking?

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Homework Help Overview

The problem involves a vector equation where the magnitude of the difference between two vectors, r and r0, is set to a constant value. The context is within the subject area of vector geometry, specifically relating to the representation of geometric shapes in three-dimensional space.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the meaning of the problem, with initial confusion about its requirements. Suggestions include testing specific values for r0 and examining the resulting equations. There is a progression from considering the problem in three dimensions to simplifying it to two dimensions.

Discussion Status

The discussion has evolved from uncertainty to a clearer understanding of the geometric implications of the vector equation. Participants have identified that the equation describes a sphere in three dimensions and a circle in two dimensions, with ongoing exploration of the role of r0 as the center of these shapes.

Contextual Notes

Participants are navigating assumptions about the geometric interpretation of the vector equation, including the implications of different values for r0 and the dimensionality of the problem.

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Homework Statement


If r = <x, y, z> and r0 = <x0, y0, z0>, describe the set of all points (x, y, z) such that the magnitude of r – r0 = 4.


Homework Equations





The Attempt at a Solution


I don't know what this problem is asking to even attempt a possible solution. Please help?
 
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If you start by trying r0 = <0, 0, 0> does that help? Can you see what that means for r?
 
Trying that I get x2 + y2 + z2 = 16 after finding the magnitude, but I still can't see what that does to r.
 
What kind of object does that equation describe?
 
What if you lose the z and reduce it to two dimensions: $$x^2 + y^2 = 16$$?
 
Including the z^2, the equation represents a sphere with radius 4. Without the z^2 it's a circle.
 
Good. And, if r_0 is the point <x0, y0, z0>?
 
I'm guessing that the reverse would be true making the components of r_0 negative, however squaring those would make that irrelevant. This is where I'm not following.
 
Think geometrically.
 
  • #10
So r_0 is the center/origin of the sphere/circle?
 
  • #11
Yes, that's it. $$|r - r_0| = 4$$ is the vector equation for a sphere of radius 4, centred at r0.

It's equivalent to $$(x-x_0)^2 + (y-y_0)^2 + (z-z_0)^2 = 16$$
 
  • #12
Wow I way over thought this.

Thanks PeroK.
 

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