What is transactional acceleration? Conceptual Question

AI Thread Summary
Transactional acceleration is not a widely recognized term, leading to confusion with translational acceleration, which refers to the change in position of an object. The discussion highlights that a falling object experiences translational acceleration, while a spinning object does not. There is a mention of hardware acceleration in the context of transactional memory, but this may not relate directly to the original question. The concept of equilibrium in a rigid body is also referenced, suggesting that it should involve translational rather than transactional acceleration. The conversation indicates a need for clarification on the terminology used in physics.
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Homework Statement


What is transactional acceleration?

Homework Equations

The Attempt at a Solution


I have been looking for it all over the internet and I can not find an explanation for it that is easy to understand
 
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THIS IS WHAT I AM READING

Equilibrium of a Rigid Body


A rigid body is in equilibrium if it has zero transactional acceleration and zero angular acceleration
 
Must be a typo. It should be translational acceleration.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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