What is Velocity at t=5s? Answer with Units

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The discussion focuses on calculating the velocity at t = 5 seconds using the slope of a distance-time graph. Participants clarify that velocity is determined by the change in position over time, specifically between t = 4 seconds and t = 6 seconds. The correct calculation involves finding the difference in position, which is -200 meters, and dividing it by the time interval of 2 seconds. This results in a velocity of -100 m/s. The emphasis is on understanding that velocity is the slope of the graph, not merely the distance divided by time.
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Homework Statement


Tell me precisely what the velocity is when the time t = 5 seconds. include the appropriate units in your answer

the picture of the problem is here click the link then zoom into see the actual queston
http://img372.imageshack.us/img372/7473/43121337ma9.th.jpg

Homework Equations





The Attempt at a Solution



I tried adding the full distance divded by 5 but the answers wrong, i aslo tried subtracting the distance then divding by the time still wrong

then i assumed that it was just the distance by it self 200 divded by 5 but that's all wrong
 
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NukeNuke said:

Homework Statement


Tell me precisely what the velocity is when the time t = 5 seconds. include the appropriate units in your answer


The Attempt at a Solution



I tried adding the full distance divded by 5 but the answers wrong, i aslo tried subtracting the distance then divding by the time still wrong

then i assumed that it was just the distance by it self 200 divded by 5 but that's all wrong

Velocity is the instantaneous rate of change of distance at a particular time.

That would be given on you graph by the slope of the line at the time asked.

Figure the slope at t=5.
 
LowlyPion said:
Velocity is the instantaneous rate of change of distance at a particular time.

That would be given on you graph by the slope of the line at the time asked.

Figure the slope at t=5.

okay so its 200 then what?

should i divide 200 by 5 or multiply it by 5 I am lost at this point
 
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NukeNuke said:
okay so its 200 then what?

should i divide 200 by 5 or multiply it by 5 I am lost at this point

What is the slope of the graph at 5?

Not the value at 5 ... the slope.

How much does it CHANGE between 4 and 6 ?
 
LowlyPion said:
What is the slope of the graph at 5?

Not the value at 5 ... the slope.

How much does it CHANGE between 4 and 6 ?

it changes 200 that's the difference
 
NukeNuke said:
This must be were I am lost at cause i have no idea what I am looking for,

The final position for your purpose at 6 is what?
The initial position at 4 is what?

The rate of change of position is Final Position less Initial Position divided by the time to change position. So figure the time difference and divide the change in position. That is your velocity. That is also the slope of the graph at all points between 4 and 6 and hence that is the velocity at all times between 4 and 6 seconds.
 
NukeNuke said:
it changes 200 that's the difference

Not exactly. It changes (-200).

And the time is what? 2 seconds?

That means that Velocity is -200m/2s = -100 m/s
 
O..okay thanks for the help
 
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