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What method of integration

  1. Apr 18, 2014 #1

    kyu

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    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution

    what method should i use? i tried

    u = x - 4
    du = dx

    i can't continue. enlighten me please
     

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  3. Apr 18, 2014 #2

    Zondrina

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    It looks like a pretty tedious partial fraction expansion.
     
  4. Apr 18, 2014 #3

    Mark44

    Staff: Mentor

    That works. Keep in mind that if u = x -4, then x = u + 4. Replace x and dx in the integral with what you have for u and du, and you'll get an integral that's easy to work with.

    An ordinary substitution will do the trick.
     
  5. Apr 18, 2014 #4

    lurflurf

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    It is neither tedious nor particularly helpful.

    $$\frac{2x+1}{(x-4)^6}=\frac{2(x-4)+9}{(x-4)^6}$$
     
  6. Apr 18, 2014 #5
    This is quite efficient to compute the integral. ;)
     
  7. Apr 18, 2014 #6
    What do you mean?
     
  8. Apr 18, 2014 #7

    LCKurtz

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    Gold Member

    He means it is easy.
     
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