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  1. Apr 23, 2005 #1
    i'm having trouble rewriting this integral:[tex]\int\frac{e^x}{e^{2x} + 1}[/tex] so that it will be in the arctan formula: should i use long divison here? if it were not for the [tex]e^x[/tex] in the numerator i'd be fine.
     
    Last edited: Apr 23, 2005
  2. jcsd
  3. Apr 23, 2005 #2
    [tex] u = e^{x}, du = e^{x}dx[/tex]

    [tex] e^{2x} = (e^{x})^2 [/tex]
     
  4. Apr 23, 2005 #3
    you never get away from u -substitutions do !!!! thanks
     
  5. Apr 23, 2005 #4
    Why woudl you watn to get away from them? They save your ass alot :)
    Learn to love em.
     
  6. Apr 23, 2005 #5
    yeah your right
     
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