What variables are needed to find a moment?

AI Thread Summary
To find the moment at the origin produced by a force, the equation Mo = r x F is essential, where r is the position vector and F is the force vector. The variables needed include the components of the force (Fx, Fy, Fz) and the coordinates (a, b, c) of the point where the force is applied. If the force is given as F = Fi, then Fx equals F, while Fy and Fz are zero. The cross product simplifies to cFx i - bFx j, indicating that only F, b, and c are necessary for the calculation. Understanding these relationships is crucial for accurately determining the moment.
Alex Katko
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Homework Statement


You wish to find the moment at the origin produced by a force, ̅F= {Fi}̂, that is applied at r= {̂ai+bj +ck ̂}. Which variables (F,a ,b,c , ) do we need to know to find a numerical answer? Explain using math and figures.

Homework Equations


Mo = r x F

The Attempt at a Solution


I know that the above equation is used to find a moment. Therefore, to me it makes sense that all variables (a,b,c,F) are needed unless you were given some sort of extra information (coordinate direction angles). Needing all the variables seems to be too simple. Any advice or hints are appreciated!
 
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Alex Katko said:

Homework Statement


You wish to find the moment at the origin produced by a force, ̅F= {Fi}̂, that is applied at r= {̂ai+bj +ck ̂}. Which variables (F,a ,b,c , ) do we need to know to find a numerical answer? Explain using math and figures.

Homework Equations


Mo = r x F

The Attempt at a Solution


I know that the above equation is used to find a moment. Therefore, to me it makes sense that all variables (a,b,c,F) are needed unless you were given some sort of extra information (coordinate direction angles). Needing all the variables seems to be too simple. Any advice or hints are appreciated!
Perform the cross product algebra and see what happens.
 
haruspex said:
Perform the cross product algebra and see what happens.
Performing the cross product gives me: (bFz-cFy)i + (cFx - aFz)j + (aFy - bFx)k. All variables (the 3 components of F and a,b,c show up).
 
Alex Katko said:
Performing the cross product gives me: (bFz-cFy)i + (cFx - aFz)j + (aFy - bFx)k. All variables (the 3 components of F and a,b,c show up).
You are given ##\vec F=F\hat i##. So what are Fx, Fy and Fz?
 
haruspex said:
You are given ##\vec F=F\hat i##. So what are Fx, Fy and Fz?
Ohh i think i am understanding. Fx = Fi. Fy = 0 Fz = 0
 
Alex Katko said:
Ohh i think i am understanding. Fx = Fi. Fy = 0 Fz = 0
Almost. Fx=F, a scalar. There is no variable Fi.
 
haruspex said:
Almost. Fx=F, a scalar. There is no variable Fi.
If Fy and Fz are both zero, then the croos product becomes cFxi - bFxj. Therefore, the variables needed are F,c, and b
 
Alex Katko said:
If Fy and Fz are both zero, then the croos product becomes cFxi - bFxj. Therefore, the variables needed are F,c, and b
Yes.
 

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