Obviously, an object which is less dense than another will float. But how much will submerge? When placed in the water, the floating object will continue to displace water, until the total weight of the water displaced is equal to the total weight of the object. Once this point is reached, the force of gravity is counterbalanced by the water's bouyancy, and it floats. This begs the question: "how much water will be displaced in terms of volume?" Well, since the water is more dense than the object, a smaller volume will be displaced. The displaced volume has an equal weight of the object. Thus: by dividing the less dense object by the denser fluid displaced, the percentage volume of the object that is submerged, which is equal to the volume of displaced water, is determined. Subtracting 100 from this give the percentage that floats.