What Went Wrong in Calculating the Volume of Gas from Decomposition?

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The discussion revolves around the calculation of oxygen gas volume generated from the decomposition of hydrogen peroxide. The initial calculation yielded 11.3 liters of O2, but confusion arose regarding stoichiometry, specifically the mole ratio of hydrogen peroxide to oxygen. Participants noted that one mole of peroxide produces half a mole of oxygen, leading to the correct volume being 22.6 liters. There are concerns about the accuracy of homework problems and the reliability of teaching assistants in providing correct solutions. Ultimately, the importance of understanding stoichiometry and clear communication with instructors is emphasized.
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So here's the problem I am faced with... dum dum dummmm

Concentrated hydrogen peroxide solutions are explosively decomposed by traces of transition metal ions (such as Mn or Fe):

2H2O2(aq) ---> 2H2O(l) + O2(g)

What volume of pure O2(g), collected at 27 °C and 746 torr, would be generated by decomposition of 61.2 g of a 50.0 % by mass hydrogen peroxide solution? Ignore any water vapor that may be present.

So first I figured that there will be 30.6g of hydrogen peroxide. Then I figured that there are 0.4498 moles of O2. Then using the ideal gas law...

V=nRT/P

I got ((0.4498)(0.08206)(27+273.15))/(746/760) = 11.3 Liters of O2

But supposedly I am wrong. Where did I go so horribly horribly wrong?

Oops, and i just punched in 22.6 Liters and it says I'm right... so where did I divide by 2 where I shouldn't have?
 
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It's impossible to locate your error since you have not shown your work.
 
Pengwuino said:
So here's the problem I am faced with... dum dum dummmm



So first I figured that there will be 30.6g of hydrogen peroxide. Then I figured that there are 0.4498 moles of O2. Then using the ideal gas law...

V=nRT/P

I got ((0.4498)(0.08206)(27+273.15))/(746/760) = 11.3 Liters of O2

But supposedly I am wrong. Where did I go so horribly horribly wrong?

You didn't read/remember the stoichiometry of the decomposition.
Oops, and i just punched in 22.6 Liters and it says I'm right... so where did I divide by 2 where I shouldn't have?

22.6? Gotta be a TA solving the problem sets --- and getting wrong answers, as is usual. You've been told where you didn't divide by two when you should have, and it's probably the same place the TA multiplied mistakenly.
 
Tom Mattson said:
It's impossible to locate your error since you have not shown your work.

Everything was already given, all I had to do was punch in the numbers. All i needed was moles and the temperature conversion and both were done correctly. The R constant is correct as well.
 
Bystander said:
22.6? Gotta be a TA solving the problem sets --- and getting wrong answers, as is usual. You've been told where you didn't divide by two when you should have, and it's probably the same place the TA multiplied mistakenly.

So 11.3 was correct?

I've been noticing a few of these problems are absolutely wrong lately in the homework. One problem had a very simple PV=nRT problem, EVERYTHING except 1 variable was missing and I did it and couldn't figure out the right answer. I show it to 4 other people... one about to graduate with his bs in physics, one his masters in physics, and 2 other people and no one could figure out what was wrong. The answer made sense (small volume, low pressure, normal temperature meant even smaller moles value) and it wasn't acording to the homework program.
 
Mole of peroxide yields half mole of O2. It's called a sitting duck.

Collateral duties of TAs include solving problem sets, checking answer keys, and keeping keys up to date when instructors change the numbers from year to year to defeat the frat-rat files --- these duties are usually performed in lackluster fashion, if at all.

Your job as a student is to bring necessary corrections to TAs' and instructors' attentions in as diplomatic a fashion as possible --- if they don't take it gracefully, you've got end of term evaluation forms.
 
Bystander said:
Your job as a student is to bring necessary corrections to TAs' and instructors' attentions in as diplomatic a fashion as possible --- if they don't take it gracefully, you've got end of term evaluation forms.

Well was I right with the first calculation (11.3)?? I am getting a little confused by everyone here :P
 
Half mole, 11 liters, yes.
 
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