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I guess there would be no flow in case 2; case 3 seems easy to me applying fluid mechanics principle; flow will be 1 to 2. But I doubt case 1; it is not in thermal equilibrium ??? Pls help
It doesn't seem practical to me also. So pls answer one that you want to acknowledge.You may assume the system will tend to go to equilibrium. What does that mean for T1 and T2 ? If they don't stay the same, then what does the change in T1 mean for P1 ?
Could you replhrase ? I don't understand what you are trying to tell me. Basically I don't answer: I help answering by asking questions. About case 1.It doesn't seem practical to me also. So pls answer one that you want to acknowledge.
Pressure is equal before; but temperature T1 is more----> They would try to attain the thermal equilibrium. When valve is being opened; I don't know what would happen; simply because I am not able to think; because I don't have numerical values how can I compare the density (say). I could say if there is density variation due to temperature difference simply flow will be from higher density to lower density side.Could you replhrase ? I don't understand what you are trying to tell me. Basically I don't answer: I help answering by asking questions. About case 1.
Is it right approach?I could say if there is density variation due to temperature difference simply flow will be from higher density to lower density side.
Not in case 2. In case 2, there will be no flow even though there are more moles in chamber 2.That means in all the cases; simply we have to find the ratio of moles of two chamber. Flow direction will be from higher to lower number of moles.
I think more moles will in chamber 1 in case 2.Not in case 2. In case 2, there will be no flow even though there are more moles in chamber 2.
Sorry. I got it backwards.I think more moles will in chamber 1 in case 2.