What will be the potential difference?

[Acez]

This is my first time on Physics Forum, so if I post this question at the wrong place please don't be annoyed.

I am a Grade 9 student and I came upon this question and don't know how to solve it:

An ammeter gives a reading of 5A when a switch was closed for 20 seconds. If this battery has 1000C of charge, what would the voltmeter read?

Please help

 

[Gokul43201]

1. This question belongs in the Homework and Coursework Section, under Introductory Physics. <it will get moved there>

2. Please read the posting guidelines (see my signature) for posting in the Homework Forums. We can not help you unless you show us your thoughts/efforts first.

 

[kyle8921]

I am happy to see your interest in physics and your willingness to seek help when you encounter a challenging question. The potential difference, also known as voltage, can be calculated using the formula V = I*t/Q, where V is the potential difference, I is the current, t is the time, and Q is the charge.

In this case, we know that the ammeter reading is 5A and the time is 20 seconds. We also know that the battery has 1000C of charge. Plugging these values into the formula, we get V = (5A * 20s)/1000C = 0.1V. Therefore, the voltmeter would read 0.1V.

I hope this helps you understand how to solve this problem. Keep up your curiosity and enthusiasm for science!