What will be the voltage across the resistor in an AC circuit?

AI Thread Summary
The discussion revolves around calculating the voltage across a resistor in an AC circuit consisting of a 250 ohm resistor, a 1.2 mH inductor, and a 1.8 micro F capacitor connected to a 120 V, 60 Hz peak source. The initial calculations yielded a voltage of 20.1 V using the peak current and resistance, but the expected answer is 14 V. The confusion arose from whether the voltage measurement was for peak or RMS values. It was clarified that the voltage meter reads RMS voltage, leading to the realization that the correct voltage across the resistor is indeed 14 V. Understanding the distinction between peak and RMS voltage is crucial for accurate circuit analysis.
jaejoon89
Messages
187
Reaction score
0

Homework Statement


Connecting a 250 ohm resistor, 1.2 mH inductor, and 1.8 micro F capacitor in series across a 120 V, 60 Hz peak source, what will the voltage be for the resistor?

Homework Equations



1) I_peak = V_app peak / Z
2) V_R = I_peak * R

?

The Attempt at a Solution


I used equation 1) to get I_peak, and then equation 2) to get V_R which I calculated at 20.1 V. The answer's 14 V and I don't understand how the book is getting this
 
Last edited:
Physics news on Phys.org
Hi jaejoon89,

jaejoon89 said:

Homework Statement


Connecting a 250 ohm resistor, 1.2 mH inductor, and 1.8 micro F capacitor in series across a 60 Hz, 120 V peak source, what will the voltage be for the resistor?


Homework Equations



1) I_peak = V_app peak / Z
2) V_R = I_peak * R

?

The Attempt at a Solution


I used equation 1) to get I_peak, and then equation 2) to get V_R which I calculated at 20.1 V. The answer's 14 V and I don't understand how the book is getting this

Were they asking for the peak voltage or the rms voltage across the resistor?
 
Ah ha! I get it now, they want the rms since it's being read by a voltage meter. Thanks!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top