What's difference between (∂y/∂x) and (dy/dx)

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Hi all.
Can anyone tell me what's difference between (∂y/∂x) and (dy/dx) and (fx) and (y`)?

Thanks.(please tell me my probable English mistakes!)

I asked this a few month ago but it seems that images in topic are not avaible (I think I have removed it from my server )
 
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∂y/∂x and fx are http://en.wikipedia.org/wiki/Partial_derivative" . They are applied to functions of several real variables, for example f(x,y)=x2+y2.

dy/dx or y' is the ordinary derivative of a function of a single real variable such as y(x)=1/x.
 
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Thank you.
and another question:
I have read this in my book =>
v=y/x
dv/dx=...

My question is : although V function has more than one variable why the author has used (dv/dx) instead of ∂v/∂x?(y and x are variables)
(you said that dy/dx is used when there is a single variable).
 
v = y/x is a commonly used substitution for solving differential equations that involve y and x. It is assumed that y is a function of x. Although v is in terms of y and x in the substitution, v is ultimately a function of x, so it's reasonable to write its derivative as dv/dx

In functions of two or more variables, as yyat mentioned, it is not assumed that anyone independent variable is related to any other independent variable.
 
Thank you all.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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