Wheatstone Bridge - Max power delivered

AI Thread Summary
In a balanced Wheatstone bridge, the net resistance can be determined, but finding the resistance for maximum power delivery requires an expression for the power delivered to the load. The current through the network is calculated as I = V/(Z+4), where Z represents the resistance of the network. The power delivered is expressed as P = I²/Z, which varies with Z. To find the specific value of Z that maximizes power, the derivative method can be employed. This approach allows for the identification of the optimal resistance for maximum power transfer.
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Homework Statement


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The Attempt at a Solution



I was able to find the net resistance as its a balanced wheat stone bridge ...

But how to find R for max power delivered?
 

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You need an expression for the power delivered to the load (not counting power lost in the 4 ohm resistance of the battery). I suggest you begin by calling the resistance of the network Z. Then the current through Z is I = V/(Z+4). The power delivered to it is P = I²/Z.
That function of Z will vary with Z and have a maximum for some specific value of Z. You could use the derivative method to find that value.
 
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