Where Does a Particle in Harmonic Motion Have Maximum Speed?

AI Thread Summary
In simple harmonic motion, a particle achieves maximum speed at the equilibrium position, which is the midpoint between the turning points. For the given positions of x1 = 100cm and x2 = 140cm, the equilibrium point is at x = 120cm. At this position, the particle's speed is highest, while maximum acceleration and net force occur at the turning points. The discussion clarifies that the question is about identifying the equilibrium position rather than the maximum speed at the extremes. Understanding the relationship between these concepts is crucial for solving related problems in harmonic motion.
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Homework Statement



A particle on a spring moves in simple harmonic motion along the x-axis between turning points at x1 = 100cm and x2 = 140cm.

[1] at which of the following positions does the particle have max speed?
100cm, 110cm, 120cm, some other position, or same greatest value occurs at multiple points?

... the questions move on to max acceleration, max net force, and such

Homework Equations





The Attempt at a Solution



I know the max speed occurs at x = 0, and when the motion reachs +- A, i know accerleation and net force are max.

But I don't get the question, please help me explain this
between turning points at x1 = 100cm and x2 = 140cm

let say I have a simple harmonic motion x in the y-axis, t in the x-axis.

Thanks
 
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The question is asking for the equilibrium position of the mass. In this example the origin of the x coordinates is not at the same position as the equilibrium position. What value of x in centimetres is the equilibrium point?
 
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