Where Is the Center of Mass in a Club Axe?

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SUMMARY

The discussion focuses on calculating the center of mass of a club axe consisting of a 9 kg stone and a 2.5 kg stick, with the stick measuring 80 cm and the stone 18 cm. To find the center of mass, the formula used is \(\sum mx / (m1 + m2)\), where \(m1\) and \(m2\) represent the masses of the stone and stick, respectively. The user expresses confusion about the calculations and seeks guidance on how to approach the problem effectively. Understanding the geometric center of both components is essential for solving the problem.

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1. a club ax that consists of a symmetrical 9 kg stone is attached to the end of a uniform 2.5 kg stick. stick is 80 cm long, stone is 18 cm.

how far is the center of mass from the handle end of the club-ax?



Homework Equations





3. i for the life of me not know how to go about solving, i am not looking for handouts i really want to learn how to do, if could please explain to me. please and thanks a lot
 
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Do you know how to find the center of mass of two points? If so, you can find the geometrical center of the stone and handle and be one step from the solution.
 
i think so, i am using \sum mx / m1 + m2.

i am just completely lost on this topic, everything i try is wrong. thanks for the help but i think i will need to figure in my next class
 

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