Where is the Least Net Force on a Roller Coaster Going Through a Vertical Loop?

AI Thread Summary
The least net force on a roller coaster going through a vertical loop occurs at the top of the loop due to the balance of gravitational and centripetal forces. While the sides may seem to have less force, the principles of circular motion indicate that the top is where riders experience the least weight. This is influenced by the gravitational field acting on the coaster. Understanding these forces is crucial for solving the problem accurately. The discussion emphasizes the importance of applying physics principles rather than guessing.
rcmango
Messages
232
Reaction score
0

Homework Statement



A roller coaster goes through a vertical loop, the net force on the coaster is the least, where?

Homework Equations





The Attempt at a Solution



I said on the sides.

however it could be at the bottom, at the top, or the same all the way around.

i assumed not much force is affecting the sides.
any help please?
 
Physics news on Phys.org
So your strategy for solving the problem is guessing? How about applying some principles of physics instead? What do you know about circular motion? What forces are required to keep an object in circular motion? There's the answer to your question right there.

EDIT: As berkeman pointed out, this object is also under the influence of a gravitational field, and that factors in too.
 
You're just guessing. Think about it more. Where do the people feel the least amount of weight? (the pressing of themselves into the seat)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top