Which Area Should Be Used to Calculate Shear Stress in a Cheese Grater Scenario?

AI Thread Summary
In the cheese grater scenario, the discussion centers on calculating shear stress, specifically which area to use: 24 cm², 96 cm², or 36 cm². The shear stress is defined as force divided by the area of the surface where the load is applied, which in this case is the upper surface of the cheese, equating to 96 cm². There is confusion regarding the definitions of shear stress and the term "normalize," but it is clarified that "normalized" refers to dividing the load by the area to derive a stress value independent of the area. The lateral force of 20 N is uniformly applied, and understanding the correct area is crucial for accurate calculations. The conversation emphasizes the importance of clarity in definitions and the application of shear stress principles.
negatifzeo
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Homework Statement


The bottom surface (8 cm x 12 cm) of a rectangular block of cheese (3 cm thick) is clamped in a cheese grater. The grating mechanism moving across the top surface of the cheese, applies a lateral force of 20 N. The shear modulus, G, of the cheese is 3.7 kPa. Assuming the grater applies the force uniformly to the upper surface, estimate the lateral movement of the upper surface with respect to lower surface?


My question is about shear stress. When calculating shear stress, which is force/area, which area do I use here? The 24 cm^2, or the 96 cm^2?
 
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Your other choice is 36 cm^2. But the shear stress is the load normalized to the area of the surface upon which the load acts. Does this answer your question?
 
I think so. I'm having a bit of trouble visualizing which surface the force is applied to from the wording of the problem, but I went ahead and solved using 24 cm^2 as my A.
 
"Assuming the grater applies the force uniformly to the upper surface..."
 
Well this is confusing to me. In my notes it says shear stress deals with the force parallel to the area. But you say it is the load normalized to the area of the surface upon which the load acts. Don't these two definitions contradict each other?
And the area of the upper surface would be equal to 96 cm^2, the same as the bottom surface, right?
 
negatifzeo said:
Well this is confusing to me. In my notes it says shear stress deals with the force parallel to the area. But you say it is the load normalized to the area of the surface upon which the load acts. Don't these two definitions contradict each other?

A parallel (or lateral) load still acts upon an area.

negatifzeo said:
And the area of the upper surface would be equal to 96 cm^2, the same as the bottom surface, right?

Yep.
 
Thank you very much for helping to clarify this for me!
 
It depends on what Mapes means here by the word "normalize." Maybe he means something like "average" (?), but I didn't see that definition in the dictionary under "normalize," so I'm not sure.
 
"Normalized" here just means that the load is divided by area to get a parameter (stress) that's independent of area.
 
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