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franjo
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wich creates an electric field charge or a charged particle (electron)
Which creates an electric field -- charge or a charged particle?
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AI Thread Summary
A charged particle, such as an electron, is responsible for creating an electric field, as charge cannot exist independently of particles. The discussion emphasizes that charge is inherently linked to charged particles, and one cannot have charge without them. It questions the existence of charge without a corresponding particle, highlighting the fundamental relationship between the two. Additionally, the concept of an electric field is described as a mathematical construct used to explain the behavior of particles. Ultimately, the consensus is that charged particles are essential for the existence of electric fields.
I'm thinking about the following problem. I have an electrified fluid with a constant charge density, Q, within the fluid. Will this necessarily yield a surface charge?
Would I have to compute it by looking at the displacement fields on either side of the interface? Would it change if the bulk charge within the fluid remains constant?
This is from Griffiths' Electrodynamics, 3rd edition, page 352.
I am trying to calculate the divergence of the Maxwell stress tensor. The tensor is given as ##T_{ij} =\epsilon_0 (E_iE_j-\frac 1 2 \delta_{ij} E^2)+\frac 1 {\mu_0}(B_iB_j-\frac 1 2 \delta_{ij} B^2)##. To make things easier, I just want to focus on the part with the electrical field, i.e. I want to find the divergence of ##E_{ij}=E_iE_j-\frac 1 2 \delta_{ij}E^2##.
In matrix form, this tensor should look like this...
Please can anyone either:-
(1) point me to a derivation of the perpendicular force (Fy) between two very long parallel wires carrying steady currents utilising the formula of Gauss for the force F along the line r between 2 charges?
Or alternatively (2) point out where I have gone wrong in my method?
I am having problems with calculating the direction and magnitude of the force as expected from modern (Biot-Savart-Maxwell-Lorentz) formula.
Here is my method and results so far:-
This...
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