Which is More Acidic: 4-Nitrophenol or 2-Fluoro-4-Nitrophenol?

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2-Fluoro-4-nitrophenol is more acidic than 4-nitrophenol due to the presence of two electron-withdrawing groups, which enhance acidity. The discussion emphasizes the importance of resonance, noting that more resonance forms lead to greater stability of the phenolate anion. The para nitro group effectively draws electrons away from the ring, further increasing acidity. The inductive effect of the fluorine atom also contributes to this increased acidity without significant interference. Overall, both electron-withdrawing effects and resonance are crucial in determining the acidity of these compounds.
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Which is more acidic, 4-nitrophenol or 2-fluoro-4-nitrophenol?

I think it would be 2-fluoro-4-nitrophenol because acidity is increased by the presence of electron withdrawing groups. 2-fluoro-4-nitrophenol has two electron withdrawing groups as opposed to only one for 4-nitrophenol. Is that correct? Should I also consider resonance when answering this question?
 
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Sounds good to me. I would say that yes, you probably should consider resonance (the more resonance forms, the more stable the phenolate anion), just to show why the para nitro group draws electrons away from the ring. Also, since there's only one F, that shouldn't interfere with anything, it'll just inductively draw electron density from the ring.
 
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