Is x +/- 3 the most simplified form for x + 3, x - 3?

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The discussion centers on whether "x +/- 3" is more simplified than writing it as "x + 3, x - 3." One participant argues that "x +/- 3" is indeed more simplified, while acknowledging that clarity may sometimes favor the expanded form. The conversation highlights that the context of the problem can influence which form is preferable, especially in cases with specific applications like graphing. Ultimately, it is suggested that if there is uncertainty, including both forms in an assignment could be a safe approach. The consensus leans towards "x +/- 3" being a valid simplified expression.
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Homework Statement



x +/- 3
is that mroe simplified then writing it out
x + 3, x - 3
I thought it would be becaue we normally say simple is when all of the operations that could be done is done in which case the second choice is more simple? I'm just woundering because I'm doing a summer assignment and have no idea if this teacher is a real jerk in grading and would mark it wrong if I put the first one done becaue it's not as simple as possible if it's not as simple as can be...

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I would go for x +/- 3 as being more simplified, but I would find it hard to believe that anyone would really quibble about a difference between that and x + 3, x - 3.
 
I would say the first is more simplified, but there are other cases where I would assume it's easier to read the separated version, for example:

2x-3y\pm(5x+3y)

versus

7x, -3x-6y

I would go with the second for this case, but for yours I would stick with the first case.
 
I think this really depends on what the information is being used for.

If the problem involves one answer, for instance, a man throwing a ball off a building (graphing a parabola), the quadratic formula would work out to the two X intercepts, but only one would be correct. In that case X=1 would be the simplified answer.

If you really have any doubt, I would just put both answers down on the assignment. I really doubt anyone would put both possibilities on a multiple choice assignment.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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