MHB Calculating Force for Lever Push - 600N

[mathmari]

Hey!

With a simple brake block we want to produce brakeforce of 600N. The friction number is 1,2. Which has to be the $F_1$ so that the lever can be pushed down??
a=60 cm, b=1,3 m

View attachment 4340

Does the following have to stand??

$$(a+b)F_1>F_2 \cdot 1,2 \cdot a$$

 

[I like Serena]

Hi! (Wave)

Does the following have to stand??

$$(a+b)F_1>F_2 \cdot 1,2 \cdot a$$

No. This will not be true. (Worried)

The method to solve a problem like this, is:

1. Make an inventory of all external forces. Which 3rd force is there? (Wondering)
2. Apply the static equilibrium conditions:
   1. Sum of the horizontal forces is zero.
   2. Sum of the vertical forces is zero.
   3. Sum of the moments (also known as torques) is zero.
   What are the resulting equations? (Wondering)
3. Solve the equations.
4. Repeat for the lever only (without the wheel).