The discussion revolves around identifying the x values where the function f(x) = 1/(x^2 + 1) is not continuous and determining if any discontinuities are removable. Participants note that the denominator, x^2 + 1, cannot equal zero, indicating there are no discontinuities in the function. The conclusion drawn is that the function is continuous everywhere. There is a consensus that the problem was likely stated correctly, affirming the function's continuity. Overall, the function has no removable discontinuities.