Which of the following has y=-1 as an asymptote?

[pooka]

Which of the following has y=-1 as an asymptote?
1.e^(-x)
2.sin(x)
3.ln x
4.x/(x+1)
5.(3-2x^2)/(2x^2-13x+7)

I've graphed each one on my calculator and I think that 1 is the answer, but it seems that it has y=0 as its asymptote rather than y=-1.

 

[rocomath]

Your calculator sucks.

Where's your work?

 

[chukie]

Your calculator sucks.

Where's your work?

I only used my calculator, but I thought about it for #4, asymptote should be x=-1 and for sin(x) there is definitely an x value for y=-1.

 

[rocomath]

I only used my calculator, but I thought about it for #4, asymptote should be x=-1 and for sin(x) there is definitely an x value for y=-1.

Are you on a 2nd username?

 

[chukie]

Are you on a 2nd username?

Sorry, I went on my brother's account by mistake.

 

[rocomath]

Sorry, I went on my brother's account by mistake.

It's okay, it was just funny to read your post as if you were pooka.

Anyways, yes sinx has the value y=-1 but would that be considered an asymptote? It bounces between |\sin x|\leq 1

How about #5? What have you learned about the powers in the numerator and denominator that relate to the asmyptote?

 

[chukie]

It's okay, it was just funny to read your post as if you were pooka.

Anyways, yes sinx has the value y=-1 but would that be considered an asymptote? It bounces between |\sin x|\leq 1

How about #5? What have you learned about the powers in the numerator and denominator that relate to the asmyptote?

Oh so the answer should be #5. I remember if you took the limit of that it would be -1, which means the horizontal asymptote is y=-1.

 

[rocomath]

Oh so the answer should be #5. I remember if you took the limit of that it would be -1, which means the horizontal asymptote is y=-1.

Yep.

\lim_{x\rightarrow\pm\infty}\frac{3-2x^2}{2x^2-3x+7}

 

[chukie]

Yep.

\lim_{x\rightarrow\pm\infty}\frac{3-2x^2}{2x^2-3x+7}

Thanks!