Which Shape Maximizes the Magnetic Field at the Center: Circle or Square?

Click For Summary

Homework Help Overview

The discussion revolves around determining which shape, a circle or a square, maximizes the magnetic field at the center when a wire of length L carrying a uniform current i is bent into either shape. Participants are exploring the application of the Biot-Savart Law and Ampere's Law in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to calculate the magnetic field for both shapes using the Biot-Savart Law, expressing uncertainty about the variable nature of r in the square case and questioning the use of Ampere's Law. Other participants suggest clarifying integral limits and consider using the finite wire formula for the square.

Discussion Status

Participants are actively discussing different approaches to the problem, with some providing references and others questioning the methods used. There is no explicit consensus yet, as various interpretations and methods are being explored.

Contextual Notes

Participants mention confusion regarding the application of different laws and the definitions of variables, indicating a need for clarification on assumptions and the setup of the problem.

stunner5000pt
Messages
1,447
Reaction score
5
you are given a wire of length L and that carries a uniform current i through it.
the wire can bent into either a circle or a square
which shape gives the maximum magnetic field at its center?

for the circle
B = \frac{\mu_{0}}{4 \pi} \int \frac{i ds \cross r}{r^3}
im not qutie sure about the s part since ds = L, riught? so ds is constant value... and so is R so we should get
B = \frac{\mu_{0} i}{4 \pi R^2}
where R = \frac{L}{2 \pi}
so B = \frac{\mu_{0} i \pi}{L^2}

now for the squar

the problem is ds is a cosntant value, but r is not because it varies from s/2 to \frac{s}{\sqrt{2}}
so what do i do? Can i use the square as an Amperian loop and solve it like so
B (s^2) = \mu_{0} i
since 4S = L, s = L/4 so
B = \frac{16 \mu_{0} i}{L^2}
thus the magnetic field at the center due to th square loop is greater becasue 4 > pi?

Also i am a bit confused as to when i use the Ampere's law and Biot Savart Law, can the Ampere's law be used for the above described situations or not?

Please help! Your advice is greatly appreciated!
 
Physics news on Phys.org
Quick reference to http://maxwell.byu.edu/~spencerr/websumm122/node70.html

shows that the solution to the Biot-savart integral for a loop is

B = \frac{\mu_o I}{2R}

Note that for the infinite wire, the solution is the same as that of Ampere's Law.

If you need to apply the integral to a square. You can do it once for one side then multiply by 4. I don't follow your method. Can you write out your integral limits more clearly.
 
Last edited by a moderator:
well for the square can i just use the equation for the finite wire of length L where d is the distance between the point int eh center and wire, and multiply by 4?

the formula I am ean to use is B = \frac{\mu_{0} i}{4 \pi d} \frac{L}{\sqrt{\frac{L^2}{4} + d^2}}}
would this yile dthe required answer
of course L in the formula does not mean the length of the wire
 
That formula does not look very familiar. Can you show the derivation?
 
its in my textbook and it would be fine if i used it i believe
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
12
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
2K
Replies
2
Views
2K
Replies
0
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K