Which Shape Maximizes the Magnetic Field at the Center: Circle or Square?

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stunner5000pt
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you are given a wire of length L and that carries a uniform current i through it.
the wire can bent into either a circle or a square
which shape gives the maximum magnetic field at its center?

for the circle
[tex]B = \frac{\mu_{0}}{4 \pi} \int \frac{i ds \cross r}{r^3}[/tex]
im not qutie sure about the s part since ds = L, riught? so ds is constant value... and so is R so we should get
[tex]B = \frac{\mu_{0} i}{4 \pi R^2}[/tex]
where [tex]R = \frac{L}{2 \pi}[/tex]
so [tex]B = \frac{\mu_{0} i \pi}{L^2}[/tex]

now for the squar

the problem is ds is a cosntant value, but r is not because it varies from s/2 to [itex]\frac{s}{\sqrt{2}}[/itex]
so what do i do? Can i use the square as an Amperian loop and solve it like so
[tex]B (s^2) = \mu_{0} i[/tex]
since 4S = L, s = L/4 so
[tex]B = \frac{16 \mu_{0} i}{L^2}[/tex]
thus the magnetic field at the center due to th square loop is greater becasue 4 > pi?

Also i am a bit confused as to when i use the Ampere's law and Biot Savart Law, can the Ampere's law be used for the above described situations or not?

Please help! Your advice is greatly appreciated!
 
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Quick reference to http://maxwell.byu.edu/~spencerr/websumm122/node70.html

shows that the solution to the Biot-savart integral for a loop is

[tex]B = \frac{\mu_o I}{2R}[/tex]

Note that for the infinite wire, the solution is the same as that of Ampere's Law.

If you need to apply the integral to a square. You can do it once for one side then multiply by 4. I don't follow your method. Can you write out your integral limits more clearly.
 
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well for the square can i just use the equation for the finite wire of length L where d is the distance between the point int eh center and wire, and multiply by 4?

the formula I am ean to use is [tex]B = \frac{\mu_{0} i}{4 \pi d} \frac{L}{\sqrt{\frac{L^2}{4} + d^2}}}[/tex]
would this yile dthe required answer
of course L in the formula does not mean the length of the wire
 
its in my textbook and it would be fine if i used it i believe