Which Track Will Have the Greater Ball Speed?

AI Thread Summary
The discussion centers on determining which of two tracks, A or B, will result in a ball having greater speed upon reaching the end. Key points include the conservation of energy principle, where potential energy lost translates into kinetic energy gained. It is suggested that if both tracks start and end at the same heights and the balls are released from rest, they should theoretically have the same speed, assuming no friction. However, the varying lengths of the tracks and the potential impact of friction complicate the conclusion. Ultimately, without additional information about friction, the final speeds of the balls cannot be definitively determined.
cutie05
Messages
3
Reaction score
0
Consider the identical balls released from rest on Tracks A and B as shown. When they reach the right ends of the tracks, which will have the greater speed?
Will The ball on track B will have the greater speed.
There is not enough information to decide.
Both will have the same speed.
The ball on track A will have the greater speed.
 

Attachments

  • e6-15.gif
    e6-15.gif
    2.1 KB · Views: 708
Physics news on Phys.org
Tough to say, since the picture is awaiting approval. The general approach should use the idea that energy is conserved. Any loss of potential energy is compensated for by an increase in kinetic energy. Your change in potential energy is reflected in the change in height (PE = mgh). Your change in kinetic energy is reflected in the change in velocity (KE=1/2 mv^2). If you lose height, the velocity has to increase. If you gain height, the velocity has to decrease.
 
Since the track lengths are different, you have know about friction. Do you ignore it?
 
Well, since the tracks both start and end at the same heights, the speed must be the same if they both start at the same speed. Using the potential energy = mgh, and the mechanical energy formula K_f + U_f = K_i + U_i.
 
You need to know if the track has friction
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top