Which wave reaches point B first?

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Homework Help Overview

The problem involves determining which type of seismic wave, a P wave or a Rayleigh wave, reaches point B first after an earthquake at point A. The context is based on the propagation of these waves through the Earth, with specific speeds given for each wave type and the distance between the two points calculated using spherical geometry.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of distance between points A and B using spherical coordinates and question the accuracy of the distance formula applied. There is uncertainty about the correct method to calculate the time taken for each wave to reach point B, with suggestions to use the basic formula V=d/t.

Discussion Status

The discussion is ongoing, with participants exploring different methods to calculate the distance and time for the waves. Some participants express confusion regarding the application of wave equations and seek clarification on the correct approach to find the time difference between the wave arrivals.

Contextual Notes

Participants note that both points A and B are at the same longitude, which simplifies the problem to a two-dimensional circular geometry. There is mention of potential discrepancies in the calculated distance affecting the results, and the need for a clear understanding of the assumptions made in the calculations.

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Homework Statement


Two points A and B on the surface of the Earth are at the same longitude and 60 deg apart in latitude. Suppose an earthquake at point A creates a P wave that reaches B by traveling straight through he body of the Earth at constant speed of 7.80m/s. The earthquake also creates a Rayleigh wave that travels along the surface of the Earth at 4.50km/s.

a) which of these 2 waves arives at B first?
b) What is the time difference in the arrival of these 2 waves at B? Take the Earth's radius to be 6,370km.




Homework Equations


well I found this online for the distance
D= R arc cos[sin(lat 1) x sin(lat 2) + cos (lat 1) x cos (lat 2) x cos [ lon 2- lon 1]]

y(x,t)= f(x- vt)

The Attempt at a Solution



well I first calculated the distance between the 2 points with the equation I found online.

D= R arc cos[sin(lat 1) x sin(lat 2) + cos (lat 1) x cos (lat 2) x cos [ lon 2- lon 1]]

R of earth= 6,370km
lat 1 = 0
lat 2= 60 deg => \pi / 3
lon 1= 0
lon 2= 0

D= 6,370km arc cos[sin(0) x sin(\pi / 3) + cos (0) x cos (\pi / 3) x cos [ 0]]

D= 6,370km arc cos [0 + 0.5]

D= 6,670.64km

x= 6,670.64km

But as to how to find the time has me confused a bit.

I think I use this equation where I just solve for time then subtract the 2 times for the different waves but I'm not 100% certain. (that's where I need help)

y(x,t)= f(x- vt)

for the 1st wave

y(6,670,640m,t)= f(6,670,640m - 7,800m/s (t))


same for the Raleigh wave

y(6,670,640m,t)= f(6,670,640m - 4,500km/s (t))

Or do I just use V= d/t and solve for t??

can someone help me out with which equation to use to find the time it takes for a wave to reach a certain distance?


Thanks
Well I'm not sure how to solve for t since isn't y the transverse position of the wave which I just don't have in the information?

Thanks a lot :smile:
 
Last edited:
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~christina~ said:
Or do I just use V= d/t and solve for t??

can someone help me out with which equation to use to find the time it takes for a wave to reach a certain distance?


Thanks
Well I'm not sure how to solve for t since isn't y the transverse position of the wave which I just don't have in the information?

Thanks a lot :smile:


The same eqn as always, which you have written down.

A and B are two points on a circle of radius R. There are two paths to be considered here; one is a straight line from A to B, and the other is the arc from A to B. If you know the angle subtended at the centre, then the dist along the paths are known, and the time is got from dist/speed.

There is absolutely no reason for considering the wave eqn here.
 
Shooting Star said:
The same eqn as always, which you have written down.

A and B are two points on a circle of radius R. There are two paths to be considered here; one is a straight line from A to B, and the other is the arc from A to B. If you know the angle subtended at the centre, then the dist along the paths are known, and the time is got from dist/speed.

There is absolutely no reason for considering the wave eqn here.

It's interesting since I got the answer incorrect from what the book has. I think the distance is what is causing this.
You didn't say whether the way I got the distance is correct or not... Below

The Attempt at a Solution



well I first calculated the distance between the 2 points with the equation I found online.

D= R arc cos[sin(lat 1) x sin(lat 2) + cos (lat 1) x cos (lat 2) x cos [ lon 2- lon 1]]

R of earth= 6,370km
lat 1 = 0
lat 2= 60 deg => \pi / 3
lon 1= 0
lon 2= 0

D= 6,370km arc cos[sin(0) x sin(\pi / 3) + cos (0) x cos (\pi / 3) x cos [ 0]]

D= 6,370km arc cos [0 + 0.5]

D= 6,670.64km

If the above way I got the distance from A=> B is incorrect then I'm not sure how I'd find it. I don't understand what you said about finding the distance.

Thanks
 
Since the two points are on the same longitude, simply think of the circle you'll get get if you slice it through that longitude. You now have to deal with just a 2-d circle, whose radius is that of the earth. The difference of the latitudes being 60 deg means that the radii from the two points subtend an angle of 60 deg at the centre.

Suppose the centre of the Earth is O. Angle AOB is given. Draw a simple diagram. Can you find segment AB? Can you find arc AB? Big calculations are not necessary, I think. :smile:

After you find the distances, use v=d/t.
 

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