WhiteningProving de Moivre's Formula for Complex Numbers?

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Homework Statement


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The Attempt at a Solution



I have literally never seen anything like this in my life. I'm in mathematical physics. I looked up de Moivre's formula and I guess this comes from a course in complex variables? I don't know why this is a homework question given that nobody in my class has actually taken it, but whatever. I need to be able to prove this. Can you please help me out, where should I start? I am familiar with geometric series and I guess I can reference De Moivre's formula. That's where I'm at. My initial thought was that this had something to do with a taylor expansion, but I know cos(x)'s taylor expansion and I don't think that has anything to do with this.
 

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Write out de Moivre's formula and see if it has the same form as one of the summands you're given.
 
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Vitani11 said:
Can you please help me out, where should I start?
Start by posting an image that is right side up.
 
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LCKurtz said:
Start by posting an image that is right side up.

Better still: do not post an image at all; type out the problem (the much preferred PF way).
 
Okay.
 
Got it, thank you Teeth
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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