Why Am I Getting Incorrect Solutions for My Quadratic Equation?

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The discussion revolves around solving the quadratic equation x² - 8x + 4 = 0, where the user struggles with the quadratic formula and ends up with incorrect solutions. The main issue identified is a misunderstanding of the formula, specifically using a plus sign inside the square root instead of the required minus sign, leading to erroneous calculations. Additionally, the user's confusion is compounded by a related problem involving the thickness of a hollow cylinder derived from a solid sphere, for which they are not obtaining the correct answer. The correct application of the quadratic formula is crucial for solving such equations accurately. Clarifying these formula details is essential for resolving the user's arithmetic mistakes.
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While solving an problem , i came to this quadratic
x2- 8x +4 =0
I couldn't break up 8x so i to solve it like this,
x= {-(-8)+√(8 2+ 4x1x4)}/2x1,{-(-8)-√(8 2+ 4x1x4)}/2x1
but the answers are coming way too absurd and negative.

The actual problem is:
"A hollow right cylinder of uniform thickness is made from the material obtained by melting a solid sphere of copper.If the diameter of the sphere is 12 cm,the height of the cylinder is 72 cm and the external radius of the base of the cylinder is 4 cm then find the thickness of the cylinder to two decimal places. "
And answer according to the book is 0.54 cm( which i am not getting !)


My doing any mistake in calculating or in the formulas?
Please help .I would be extremely grateful!
 
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It's just a silly little arithmetic mistake. The quadratic formula is
<br /> x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}<br />

You have pluses inside the radical in both cases.
 
Yes , i did that .
So what's wrong?
 
You were already told - you have plus inside the radical. Formula calls for minus.
 
Like I said, you have \sqrt{b^2 + 4ac} instead of \sqrt{b^2 - 4ac}.
 
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