Why are the constants a and b independent of temperature in gas properties?

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The constants a and b in gas properties are intrinsic characteristics of a gas and are considered independent of temperature. The constant b represents the actual volume occupied by gas molecules, while a accounts for intermolecular forces affecting pressure. Although volume is temperature-dependent, the relationship between pressure and volume in the context of these constants remains constant due to the nature of intermolecular forces. As temperature increases, intermolecular distances may increase, but the fundamental properties represented by a and b are approximated to remain stable. Understanding these concepts clarifies why these constants do not vary with temperature.
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Homework Statement


My book says that the constants a and b are characteristic properties of a gas, and they do not depend on temperature. But i am having trouble understanding it.

Homework Equations

The Attempt at a Solution


We know, a = ΔP*V2 / n2 , but volume is temperature dependent, so how can a be temperature independent? One explanation can be that as V increases then ΔP will decrease, so that the ratio remains constant, but i am not sure.
Similarly as I increase the temperature, volume will increase, hence b decreases, as the gas approaches ideality. Please help me out.
 
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Hello,

subhradeep mahata said:
but volume is temperature dependent
indeed it is. But that is a 'different volume'.

the ##b## in the van der Waals equation of state refers to the 'actual' volume of the molecules themselves. In other words: the equivalent volume of the molecules if they are considered as hard spheres. The volume the gas assumes under a given pressure and at a given temperature is much greater: most of that is simply empty space trough which the molecules move at considerable speeds. ##b## follows when you go to zero Kelvin and classically the molecules don't move any more.

##a## is a first correction on the pressure: in the ideal gas law there are no intermolecular forces and ##pV = nRT##. In a real gas there is a small, almost always attractive, force between the molecules that reduces the pressure.
 
Okay, i understood the case of b.
But i need some clarifications regarding a.
If temperature increases, won't the intermolecular force and hence 'a' decrease ?
 
Last edited:
The forces decrease because the intramolecular distances increase. The effect on the pressure in lowest order is best approximated with ##a\displaystyle \left ( n\over V \right )^2 \ .##

Google intramolecular forces, van der Waals force, Lennard Jones potential
 
As long as all electrons are in their ground state "volume" of the molecules and strength of intermolecular forces can be assumed constant (that's not entirely true, but it is quite a good approximation). In temperatures where the VdV equation is used electrons don't get excited.
 
subhradeep mahata said:

Homework Statement


My book says that the constants a and b are characteristic properties of a gas, and they do not depend on temperature. But i am having trouble understanding it.

Homework Equations

The Attempt at a Solution


We know, a = ΔP*V2 / n2 , but volume is temperature dependent, so how can a be temperature independent? One explanation can be that as V increases then ΔP will decrease, so that the ratio remains constant, but i am not sure.
By your mathematical rationale, in the ideal gas equation PV=nRT, the ideal gas constant R should be a function of the pressure, the volume, the number of moles, and the temperature. Is that correct?
 
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