Why are these capacitor in parallel?

In summary, the conversation discusses the confusion surrounding whether two opposite polarity charged capacitors are in series or parallel. The use of terms like series and parallel may not always help in understanding the problem. The circuit is being used in a way that causes current to flow clockwise, which leads to the discharge of one capacitor and the charging of the other. The final condition of the circuit is independent of any resistance and depends on charge conservation. The equivalent series resistance is zero in this case, regardless of frequency. The final situation can only be determined after current has finished flowing and a lot of the initial energy stored in the capacitors is dissipated.
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  • #2
Tiago3434 said:
It says that the capacitors are in parallel,
Using terms like Series and Parallel doesn't always necessarily help in understanding this sort of problem. As far as points a and b are concerned and, if the switches are connected with the two capacitors uncharged, you can look upon them as being in parallel (the same as if they were resistors). But that isn't how the circuit is being used; a current will be flowing around the ('series') loop. It has to be true to say that, after everything has settled down, (but not initially) the top pair of terminals will be at the same potential and the bottom two will be at the same potential (both pairs are held together)
What you have, when the switches are on, is a loop with the PD's on the two capacitors acting in a sense which will cause current to flow clockwise. Unfortunately, the problem is slightly nonsensical because, as with all 'ideal' situations, the current flow would need to be instantaneous and infinite and, in fact, the circuit would oscillate due to the inherent Inductance of the loop and radiate Energy like a loop antenna, ( analogous to two taught springs suddenly connected in the middle with one pulling and one pushing). The clockwise current will discharge the 1μF capacitor and charge it from the 3μF capacitor in the other sense until equilibrium (equal PDs) is established.
You have to assume some finite resistance in the circuit and you can only consider the final situation, after current has finished flowing. A lot of the original Energy, stored in the capacitors has 'disappeared' by being dissipated in the resistance of the wire.
 
  • #3
Tiago3434 said:
It says that the capacitors are in parallel, but why? I can´t understand this point, and it certainly seems as if they are in series

they are only in parallel if both switches S1 and S2 are closed, else the capacitor on the right plays no part in the circuit

upload_2017-11-22_11-23-48.png
this wouldn't matter if they were resistors, capacitors, inductors or many other componentsDave
 

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  • #4
Ah, until I saw the referenced diagram, I thought it might be down to 'Equivalent Series Resistance', which is frequency-dependent...
 
  • #5
Nik_2213 said:
Ah, until I saw the referenced diagram, I thought it might be down to 'Equivalent Series Resistance', which is frequency-dependent...
The "Equivalent Series Resistance" is zero in this case, independent of frequency, which shows the nonsensical nature of the problem, as posed initially. The final condition of the circuit is independent of any resistance and just hangs on Charge Conservation. You calculate the two charges (they have different signs, however you choose to take the origin) and the net charge will be shared between the two capacitors, which will have the same PD across them. The 3μF capacitor will have three times the charge of the 1μF capacitor.
 

1. Why are capacitors connected in parallel?

Capacitors are connected in parallel to increase the total capacitance and to share the voltage across each capacitor. This allows for a larger storage of charge and a more stable voltage supply.

2. How does connecting capacitors in parallel affect the total capacitance?

Connecting capacitors in parallel increases the total capacitance. The formula for calculating the total capacitance in parallel is Ctotal = C1 + C2 + C3 + ..., where C1, C2, C3, etc. are the individual capacitances of each capacitor.

3. What happens to the voltage across each capacitor when they are connected in parallel?

The voltage across each capacitor remains the same when they are connected in parallel. This is because the voltage is shared across all the capacitors, resulting in a more stable voltage supply.

4. Can I mix capacitors with different capacitances in parallel?

Yes, you can mix capacitors with different capacitances in parallel. The total capacitance will be the sum of all the individual capacitances, and each capacitor will still have the same voltage across it.

5. How does connecting capacitors in parallel affect the overall capacitance in a circuit?

Connecting capacitors in parallel increases the overall capacitance in a circuit. This is because the total capacitance is the sum of all the individual capacitances, resulting in a larger storage of charge and a more stable voltage supply.

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