garyljc
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I was wondering if anyone could show me why b^[log (base b) a ] is = a ?
D H said:The equation
b^{\log_b a} = a
is better written as
b^{\log_b a} \equiv a
In other words, the equality is true by definition.
garyljc said:is it possible to prove it ? like simplify it then showed that it is equal to a ?