garyljc
- 103
- 0
I was wondering if anyone could show me why b^[log (base b) a ] is = a ?
D H said:The equation
[tex]b^{\log_b a} = a[/tex]
is better written as
[tex]b^{\log_b a} \equiv a[/tex]
In other words, the equality is true by definition.
garyljc said:is it possible to prove it ? like simplify it then showed that it is equal to a ?