Why Can T-Butyl Chloride Undergo Substitution but Isopropyl Chloride Cannot?

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T-butyl chloride can undergo substitution reactions to form C4H9OH, while isopropyl chloride cannot due to its structure. The discussion highlights that T-butyl chloride is a tertiary halide, allowing for easier substitution, whereas isopropyl chloride is a secondary halide, which complicates the process. The presence of an extra carbon in T-butyl chloride facilitates this reaction. Additionally, while isopropyl chloride can produce 2-methylpropanol through addition reactions, this does not apply to substitution. Ultimately, the key factor is the difference in halide types and their reactivity in substitution reactions.
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Homework Statement


T-butyl chloride can undergo substitution reaction to create C4H9OH, but isopropyl chloride cannot. Why is this?


Homework Equations





The Attempt at a Solution


I'm guessing it has to do with the extra carbon. Maybe since it is a secondary halide, the substitution takes the H off instead of the Cl?
 
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physics(L)10 said:

Homework Statement


T-butyl chloride can undergo substitution reaction to create C4H9OH, but isopropyl chloride cannot. Why is this?


Homework Equations





The Attempt at a Solution


I'm guessing it has to do with the extra carbon. Maybe since it is a secondary halide, the substitution takes the H off instead of the Cl?

Well, you can form 2-methylpropanol from IPA via things like metallation and addition of formaldehyde, but this is addition, not substitution. So the only thing that's relevant here is the number of carbons, in my opinion.
 
That's a trick question.
 
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