Why can you only contract one field in the Wilson approach to renormalization?

nikol
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When I am reading about the Wilson approach to renormalization in Chapter12.1 of Peskin & Shroeder I am wondering why are you allowed only to contract the \hat{\phi} field (this is the field that carries the high-momentums degrees of freedom)as they show in equation 12.10, I thought that we should add all the contractions, between all the 4 fields and here is the term they are making the example of:
\int \mathcal{D}\hat{\phi}exp\left(-\int d^{d}x \frac{\lambda}{4}\phi^{2}\hat{\phi}^{2}\right)
 
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Here we are only doing the path integral over the ##\hat\phi## field, and not integrating over ##\phi##. You can only get internal lines in a Feynman diagram for fields you are integrating over. So we end up writing down Feyman diagrams where all the external lines are ##\phi## fields (because we only care about the interactions of low-energy particles) and all the internal lines are ##\hat\phi## fields (because we are only integrating over the high-momentum modes).
 
Thank you I think I almost understand. Another thing I am noticing is that while integrating over the high degrees of freedom \hat{\phi} the dependence of the large cutoff \Lambda goes into the coefficients (see for example the expression of \mu in formula 12.11 or for \lambda^{'} in 12.29). Are we to assume that we will no longer have any cases that as \Lambda->\infty that will not cause any of those coefficients to go to infinity? and if so is that only valid for theories that are renormalizable?
 
nikol said:
When I am reading about the Wilson approach to renormalization in Chapter12.1 of Peskin & Shroeder I am wondering why are you allowed only to contract the \hat{\phi} field (this is the field that carries the high-momentums degrees of freedom)as they show in equation 12.10, I thought that we should add all the contractions, between all the 4 fields and here is the term they are making the example of:
\int \mathcal{D}\hat{\phi}exp\left(-\int d^{d}x \frac{\lambda}{4}\phi^{2}\hat{\phi}^{2}\right)
you will have the effect of it in higher order terms,where you will have two vertices for example.just see 12.13.
 
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