Why derive electric field produced by a rod?

AI Thread Summary
Deriving the electric field produced by a charged rod has practical applications, particularly in understanding the electric field between parallel plates, which is uniform and beneficial for experimental setups. The discussion emphasizes the significance of the 1/r dependence of the electric field at great distances, especially concerning safety around high-voltage power lines. The electric field beneath a 700 kV power line is noted to be influenced by its quasi-electrostatic nature rather than radiation effects, given the low frequency of 50 or 60 Hz. Additionally, the conversation touches on the minimum diameter required for high-voltage power lines to prevent corona discharge. Overall, the focus is on the implications of static electric fields in practical scenarios.
damosuz
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Is there a practical utility to derive the electric field produced by a charged rod (and the 1/r dependence at great distance)? I know it can be useful to derive the electric field produced by a large plate since you can then show that the field between close parallel plates that are oppositely charged is uniform, which is useful info for experimenters.
 
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damosuz said:
Is there a practical utility to derive the electric field produced by a charged rod (and the 1/r dependence at great distance)? .
What is the electric field 50 feet below a 700 kV interstate high-voltage power line (= long rod)? (ac power lines are actually 3 phase).

What is the minimum diameter of a high voltage power line to prevent corona?

Bob S
 
I meant the electric field produced by a static charge on a rod, not the intensity of the electric field in the radiation produced by the ac current in a wire (which is 1/r dependent too).
 
damosuz said:
I meant the electric field produced by a static charge on a rod, not the intensity of the electric field in the radiation produced by the ac current in a wire (which is 1/r dependent too).
At 50 or 60 Hz, the radiation (like from antenna) is minimal, so the power line problem becomes quasi-electrostatic. The high-tension power line hazard is the quasi-electrostatic field, not a radiation field.

Bob S
 
Bob S said:
At 50 or 60 Hz, the radiation (like from antenna) is minimal, so the power line problem becomes quasi-electrostatic. The high-tension power line hazard is the quasi-electrostatic field, not a radiation field.

Thank you for your help. Do you have any reference about this?
 
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