Why Do Closed Pipes Not Produce Even Numbered Harmonics?

AI Thread Summary
Closed pipes cannot produce even-numbered harmonics due to their physical structure, which requires a pressure antinode at the open end and a node at the closed end. This configuration allows only odd harmonics, such as the first overtone, which occurs at three times the fundamental frequency. The absence of even harmonics is explained by the inability to satisfy the boundary conditions necessary for even harmonics, as they would require a different arrangement of nodes and antinodes. Understanding this concept is crucial for physics exams, as it highlights the relationship between pipe length and wavelength. Mastery of these principles can significantly improve exam performance.
nina
Messages
11
Reaction score
0
Why can't closed pipes produce even numbered harmonics? I have been given an explanation, but it isn't very detailed. I'm doing A2 (or just A level) physics, so an explanation suitable for this level would be greatly appreciated!
Thanks.
 
Physics news on Phys.org
What explanation have been given to you so far
 
Just that the 1st overtone has a frequency of 3 times the fundamental frequency, therefore the second harmonic is missing.

Is that all I need to know? It doesn't seem much of an explanation to give in an exam.

Thanks for your help...
 
yup it not enough Can u calulate the wavelength in terms of L
 
Yes, I can calculate the wavelength from L. But why is there no second harmonic in a closed pipe?
 
Coz for Even harmonics u need a arrangement like this
2f, 4f which is clearly not possible

And u never get L = even integer * Wavelength
 
Thanks! I will look at that more closely. thanks for the link too.:smile:
 
basically it is due to the fact that there is pressure antinode and node at closed and open ends
 
  • #10
actually, it makes sense now.
thank you so much. i may just get a good grade in my exam now...
:smile:
 
  • #11
Goodluck for exams
 
Back
Top