Why do I have to multiply by -1 when simplifying (sometimes)

  • Thread starter Thread starter Jherek
  • Start date Start date
  • Tags Tags
    Simplifying
AI Thread Summary
The discussion revolves around solving the equation -4su + 7t + 9u + 2 = 6t + 4u - 9 for s. The participant initially arrives at an answer that differs from the provided solution due to confusion over the multiplication by -1. It is clarified that the right side was simplified by factoring out -1, which is a common convention to avoid negative signs in the denominator. The left side remains unchanged because multiplying by -1 does not alter its value. Ultimately, the participant acknowledges that their answer is equivalent but does not adhere to conventional simplification practices.
Jherek
Messages
4
Reaction score
0

Homework Statement



Solve for s:
-4su+7t+9u+2=6t+4u-9

Homework Equations



The Attempt at a Solution


My answer:
s = \frac{-t-5u-11}{-4u}
The given answer:
s=\frac{t+5u+11}{4u}
I know that the right hand side has been multiplied by -1, but this raises some questions in my mind; Why do I have to do this, is my answer wrong and why isn't the left hand side also multiplied by -1?
Thanks for your help...
 
Physics news on Phys.org
They haven't multiplied anything by -1. They factored -1 out from both the numerator and denominator and canceled it. Your answer is equivalent, but it's pretty typical to not leave any minus signs in denominators when simplifying.
 
Ah. So that explains why the left-hand side is left untouched. It looks like the right hand side has been multiplied by -1 and that is how I've heard it explained before - but what you say makes more sense!
So I wasn't actually wrong as such, just not following convention.
Thank you.
 
Jherek said:
Ah. So that explains why the left-hand side is left untouched. It looks like the right hand side has been multiplied by -1 and that is how I've heard it explained before
I suspect that what you were told is that on the right-hand side "we can multiply both "top" and "bottom" by -1[/color]". This is equivalent, if you think about it, to multiplying by 1 since (-1)/(-1) = 1. And when anything is multiplied by 1 you don't change its value. Hence, the left-hand side remains unchanged when you multiply the right-hand side by 1. (Remember, -1/-1 = 1)
 
After all, which is simpler, \displaystyle \frac{\,-3}{\,-4} or \displaystyle \frac{3}{4}\ ?
 
Well, I have to say that to me, they both look equally as simple! Especially if we were in the habit of writing \frac{+3}{+4} which we don't so I'll just have to go along with what's expected!
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top