Why Do Sparks Occur at the Head of an Electric Train?

  • Thread starter Thread starter Kolahal Bhattacharya
  • Start date Start date
  • Tags Tags
    Head Spark
AI Thread Summary
Sparks at the head of an electric train occur primarily due to momentary loss of contact between the train's pantograph and the overhead wire or third rail. This disconnection leads to a high back electromotive force (emf) that attempts to maintain the connection, resulting in a spark. The significant potential difference between the energized and de-energized points, combined with the thin layer of air acting as an insulator, facilitates the spark formation. If the train were in a vacuum, no spark would occur due to the absence of air. Understanding these dynamics is crucial for grasping the electrical interactions in electric train systems.
Kolahal Bhattacharya
Messages
133
Reaction score
1

Homework Statement



When an electric train runs,we are familiar to the sparks at the end of cable connections.Why does it occur?Is it due to voltage fluctuations?

Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
Kolahal Bhattacharya said:

Homework Statement



When an electric train runs,we are familiar to the sparks at the end of cable connections.Why does it occur?Is it due to voltage fluctuations?

Homework Equations





The Attempt at a Solution

Are you talking about the sparks between the train's pantograph pickup and the overhead energized wire catenary, and the sparks that occur between an energized third rail and the contact pickups on the train? If so, these sparks occur only occasionaly at areas where full contact between the wires or energized rail is momentarily lost. Based on this momentary loss of contact, can you explain why sparks might occur in this situation?
 
I cannot really understood your technical terms...However,I hope you are talking about the same problem.I should say the structure is like a wire over a structure like < whose base is attached to the train.
Well,what I suppose,during the momentary cut of contact,the back emf=-LdI/dt is high which desparately tries to retain the connection.So,a spark is seen.
 
Kolahal Bhattacharya said:
I cannot really understood your technical terms...However,I hope you are talking about the same problem.I should say the structure is like a wire over a structure like < whose base is attached to the train.
Well,what I suppose,during the momentary cut of contact,the back emf=-LdI/dt is high which desparately tries to retain the connection.So,a spark is seen.
It's not the induced voltage that causes the spark. There is a large potential difference in emf between ther enegized wire and contact that has been de-energized during the momentary loss of contact. . Air, normally a very good insulator, lies between those 2 points. It is a very thin layer. What happens that causes teh spark (arc)? Note: if this train was riding in a vacuum, there would be no spark.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top