Why does a gas behave as ideal if the Isotherm and Isenthelp

  • Thread starter Thread starter ScareCrow271828
  • Start date Start date
  • Tags Tags
    Gas
AI Thread Summary
A gas behaves ideally when the isotherm and isenthalp are parallel because, for an ideal gas, internal energy is a function solely of temperature. This means that if the temperature remains constant, the internal energy will also remain constant, leading to u1 equaling u2. The relationship h = u + pv indicates that changes in enthalpy are related to changes in internal energy and pressure-volume work. Therefore, the equality of internal energy in an ideal gas process is due to its dependence on temperature alone. Understanding these principles clarifies the behavior of gases under ideal conditions.
ScareCrow271828
Messages
22
Reaction score
0

Homework Statement



Why does a gas behave as ideal if the Isotherm and Isenthalp are parallel.

Homework Equations


h=u+pv
T1=T2, P1V1=P2V2

The Attempt at a Solution


[/B]
h1=u1+p1v1, h2=u2+p2v2
h2=h1 so
u1+p1v1=u2+p2v2
and p1v1=p2v2
Does that mean internal energy for an ideal gas is zero?
I don't understand. Thanks in advance!
 
Physics news on Phys.org
No. It means that u1=u2
 
  • Like
Likes ScareCrow271828
Chestermiller said:
No. It means that u1=u2
Thanks! Why would internal energy be equal for an ideal gas process??
 
ScareCrow271828 said:
Thanks! Why would internal energy be equal for an ideal gas process??
For an ideal gas, the internal energy per unit mass is a unique physical property that depends only on the temperature, irrespective of the process. So, if the temperature is the same, the internal energy is the same.
 

Thread 'Rolling without slipping on a curved surface'

Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
View full post »

Similar threads

Ideal Gas Equation and Polytropic Constant
Replies
3
Views
5K
Irreversible adiabatic expansion in which P_ext=0
Replies
13
Views
3K
Find Heat Energy Needed to Expand Gas to Triple Volume
Replies
2
Views
2K
Adding energy to an ideal gas without changing internal energy
Replies
2
Views
2K
Calculate Work (w) for Isothermal Gas Expansion/Compression
Replies
4
Views
2K
How to derive pv^gamma=constant
Replies
4
Views
12K
Is PV^gamma Constant in Adiabatic Processes?
Replies
9
Views
5K
How Does Changing Temperature and Pressure Affect Gas Density?
Replies
3
Views
2K
Spherical bubble rises to surface, Ideal Gas, Thermal Energy
Replies
5
Views
4K
How does pressure energy influence fluid flow in a tube with varying heights?
Replies
1
Views
1K

Hot Threads

Recent Insights

Back
Top