Why does an object have constant speed with Centripetal Force

AI Thread Summary
A satellite maintains a constant speed in orbit due to the balance between gravitational force and centripetal force, which acts as the necessary force for circular motion. The satellite's initial tangential velocity, imparted during its launch, allows it to move sideways while being pulled towards Earth, creating a continuous free-fall around the planet. If the initial velocity is sufficient, the satellite will maintain a stable orbit; otherwise, it may fall to Earth or enter an elliptical path. The speed remains constant because both centripetal acceleration and the radius of the orbit are constant, ensuring that the satellite does not accelerate towards Earth. Thus, the satellite's motion exemplifies the principle of an object in free-fall that continuously misses its target.
Masafi
Messages
58
Reaction score
0
Hi, I understand how centripetal force works and all. But I still don't understand, when looking at a satellite orbiting the Earth, the only force acting is its weight, which is in the direction of the Earth.

How does its circular motion start in the first place? If the only force there is is acting towards the Earth, why doesn't it just move towards the Earth? Surely something must happen to get the circular spin to begin, like with a hammer thrower, they spin it physically to begin the motion.

Why does a fixed distance remain from the Earth? And also, why does its speed not change at all?
 
Physics news on Phys.org
Masafi said:
Hi, I understand how centripetal force works and all. But I still don't understand, when looking at a satellite orbiting the Earth, the only force acting is its weight, which is in the direction of the Earth.

How does its circular motion start in the first place? If the only force there is is acting towards the Earth, why doesn't it just move towards the Earth? Surely something must happen to get the circular spin to begin, like with a hammer thrower, they spin it physically to begin the motion.

Why does a fixed distance remain from the Earth? And also, why does its speed not change at all?
In the case of the circular motion of a satellite, the weight of the satellite is also its centripetal force. In a circular motion with constant speed, the only force applied on the body is precisely the centripetal force, so all is coherent.

Why does the satellite does not fall over the Earth if the only force is toward the center of the Earth? Because as you said, something made it start to move in a circular motion. The original impulse has to be applied perpendicularly to the centripetal force. If it has enough impulse, the motion will be circular. If it has a too tiny impulse it will eventually fall over the Earth. If it has an impulse bigger than the one required for the circular motion, I think the motion will be elliptic, but I'm not 100% sure.

The speed is the magnitude of the velocity. In a circular motion, a_c=\frac{v^2}{r}. In the case of the satellite, a_c ( and r) is constant, making that v (the speed, and not velocity) must be constant.

I'll let others to explain it better than I. Do you still have doubts?
 
fluidistic said:
In the case of the circular motion of a satellite, the weight of the satellite is also its centripetal force. In a circular motion with constant speed, the only force applied on the body is precisely the centripetal force, so all is coherent.

Why does the satellite does not fall over the Earth if the only force is toward the center of the Earth? Because as you said, something made it start to move in a circular motion. The original impulse has to be applied perpendicularly to the centripetal force. If it has enough impulse, the motion will be circular. If it has a too tiny impulse it will eventually fall over the Earth. If it has an impulse bigger than the one required for the circular motion, I think the motion will be elliptic, but I'm not 100% sure.

The speed is the magnitude of the velocity. In a circular motion, a_c=\frac{v^2}{r}. In the case of the satellite, a_c ( and r) is constant, making that v (the speed, and not velocity) must be constant.

I'll let others to explain it better than I. Do you still have doubts?

Well, why does the magnitude of the velocity, i.e. the speed, remain constant? Why doesn't it accelerate closer towards the Earth?

If something has a force, say a person dragging something, why does that go towards the person, whilst in a circular motion, it spins around?
 
Masafi said:
Why doesn't it accelerate closer towards the Earth?
Well, it does. But its tangential velocity carries it past Earth. An orbiting body could be viewed as a falling body that keeps missing its target.
 
DaveC426913 said:
Well, it does. But its tangential velocity carries it past Earth. An orbiting body could be viewed as a falling body that keeps missing its target.

And why doesn't it hit the target? Why is there a tangential acting velocity?
 
Masafi said:
And why doesn't it hit the target? Why is there a tangential acting velocity?

The object was initially imbued with it.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top