Why Does Binding Energy Differ Between ^6Li and ^7Li?

AI Thread Summary
The discussion focuses on the differences in binding energy between ^6Li and ^7Li as explained by the semi-empirical mass formula. It highlights that the binding energy for ^7Li (A=7, Z=3) is greater than that of ^6Li (A=6, Z=3), which may be attributed to the effects of pairing energy and the odd-even rule. The odd-even rule indicates that nuclei with an odd number of protons or neutrons tend to have lower binding energy compared to those with even numbers. The participant expresses confusion over the calculations and the implications of these concepts. Understanding these factors is crucial for comprehending nuclear stability and binding energy variations.
Taylor_1989
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Homework Statement


Q: With reference to the semi-emprical mass formula, explain why one binding energy is greater than the other?

The element in question is ##^6 L_i## & ##^7L_i##

Homework Equations

The Attempt at a Solution


So far from what I have read I think the part of the equation they are ref to is the parity part have I got this correct? My issue is I am really trying to understand why it changes I look at the equation more and more and get confused by playing with the number and pluggin them into the equation, I have noticed for a A=7 and Z=3 the binding energy is higher but for A=6 and Z=3 the binding energy is lower. I did read some about odd even, but it did not make sense at the time, but it seem from just the number I plug in, that for odd even you have a lower binding energy than with an odd, odd but why is this?
 
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