Why Does Charge Q Not Appear in the Equilibrium Equation for Helium Balloons?

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The discussion centers on a problem involving two charged helium balloons in equilibrium, where the total force on each balloon is zero. The confusion arises regarding the role of the electrostatic charge "Q" in the equilibrium equation. It is clarified that while the forces exerted by the balloons on each other cancel out, the horizontal forces include both the electrostatic force and the tension in the string. To solve for "Q," one can analyze the tension in the ropes as if they were simply hanging from two ropes, recognizing that the repulsion between the balloons counteracts the tension pulling them together. Understanding these forces is crucial for determining the charge on the balloons.
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HI Guys!

Please help me in solving this simple problem. I am getting an answer which is not matching with the answer given in my book. The problem is:

"TWO SMALL HELIUM FILLED BALLONS, TIED TO A 50gm WEIGHT FLOAT IN EQUILIBRIUM.(TOTAL FORCE ON EACH BALLOON IS ZERO). EACH BALLOON HAS A CHARGE "Q". FIND "Q".
See attached fig also:

now i have tried it many times. what I am confusing that suppose i take one ballooon under consideration. Then the force that is exerted by the second balloon on the first one and the force exerted by the 1st on the second will cancel each other. so there would be no expression left with the term "Q".

Please help me, i have a very short time.

Thanks in advance!
 

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Take a single balloon. Note that the horizontal forces on this balloon include the electrostatic force and a component of the tension in the string, and that the horizontal forces sum to 0.
 
An approach: If instead of balloons you just had the mass hanging from two ropes, could you find the tension in the ropes? If you can do that, you will know that the ropes are pulling the two balloons together. The repulsion is counteracting the force pulling them together.
 
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