Why Does Increasing Friction Not Lift an Object Against Gravity?

AI Thread Summary
Increasing friction does not lift an object against gravity because friction is a reactive force that depends on the normal force, which in this case is the weight of the object. The friction force can only reach a maximum equal to the weight of the object, meaning it cannot exceed this limit regardless of how hard one pushes. Adding weight to the object can increase the friction force, allowing it to resist greater downward forces. The direction of the applied force also matters; in this case, pushing perpendicular to the wall does not contribute to lifting the object. Thus, friction alone cannot overcome gravitational force to lift the object.
AlbertE97
Messages
10
Reaction score
0
The harder I push a book to a wall, the larger is the friction force, since friction is (coefficient of friction (times) the force I use).

Why won't the friction force make the object go up instead of stay where it is since the friction worse can get arbitrarily large while gravitational force is constant?

(not a homework question but one I thought of)(English is my 2nd language)
 
Physics news on Phys.org
Friction is a reactive force, so you need another force to create the friction. In your case, the force is the weight of the book so the friction force will never be greater than the weight of the book.

What the coefficient of friction times the normal force equation tells you is the MAXIMUM force that friction can handle. So by pushing harder you do not increase friction, but if you would add another force pushing the book down (say adding weight on it), the friction force could still resists the increased downward force.
 
It is not clear in your original statement which direction you are pushing the book (parallel to the wall or perpendicular to the wall?).

What Jack said was very good.
 
Dr.D said:
(parallel to the wall or perpendicular to the wall?)

Perpendicular.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top