Why Does Induced Current in a Solenoid Flow Left to Right?

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Induced current in a solenoid flows from left to right due to the principles of electromagnetism. When resistance decreases, the current in solenoid X increases, leading to a rise in magnetic flux density. According to Lenz's law, solenoid Y generates an induced current to oppose this change, resulting in a magnetic field directed from right to left. The right-hand grip rule confirms that the current through the ammeter flows left to right. The reasoning presented aligns with established electromagnetic principles.
Clara Chung
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The Attempt at a Solution


The answer of 2c is : Current through A to the left.
But I think it is to the right.
By I=V/R, a reduced resistance R results in an increase of current through solenoid X. By B=unI, an increase in current causes the magnetic flux density to increase(where field lines point right). By lenz's law there will be an induced current in solenoid Y to produce a magnetic field opposite to the increase of magnetic field in X, which points from right to left. By right hand grip rule the current flows from left to right through the ammeter.
Why am I wrong. Thanks
 
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I agree with you. Part c is similar to part a.
 
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Clara Chung said:
By I=V/R, a reduced resistance R results in an increase of current through solenoid X. By B=unI, an increase in current causes the magnetic flux density to increase(where field lines point right). By lenz's law there will be an induced current in solenoid Y to produce a magnetic field opposite to the increase of magnetic field in X, which points from right to left. By right hand grip rule the current flows from left to right through the ammeter.
Your reasoning sounds correct to me.
 
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