Why Does Mass M Move at u/cosθ in a Pulley System?

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In a pulley system where two ends of an inextensible string move downwards with a uniform speed u, the upward speed of mass M is determined to be u/cosθ. Initially, there was confusion regarding the velocity components, as it seemed they should add up to 2ucosθ. However, the correct interpretation involves understanding that the strings are not moving transversally, and the vertical components of the strings' velocities do not simply sum up in that manner. A key insight is that as the angle approaches 90 degrees, the relationship yields an infinite velocity, which is incorrect, reinforcing that the upward speed is indeed u/cosθ. The discussion clarifies the importance of analyzing the geometry of the system rather than relying solely on intuitive assumptions.
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Homework Statement



In the arrangement as shown in the figure below, the ends P and Q of an inextensible string move downwards with uniform speed u. Pulleys A and B are fixed. Mass M moves upward with a speed:

a. 2ucosθ
b. u/cosθ
c. 2u/cosθ
d. ucosθ

2tRxY.png

Homework Equations



None, I am not sure whether it falls under general physics or homework section. [/B]

The Attempt at a Solution



The strings move with velocity u in their respective directions , thus block will move with velocity 2ucosθ. Since each of the two strings has velocity in vertical direction as ucosθ .

But the answer says it is u/cosθ . Which seems right as when you take components of this total velocity of block M in directions of strings, it gives components as u, but those 2 components don't add up to 2ucosθ. What is the mistake here ? Why are they not adding up to ucosθ?

Thank you for all the support and help.
 
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The strings are not moving along their transversal direction. They are getting shorter at a given rate. Based on trigonometry, you can find how much shorter the strings become when the mass moves up a certain distance.
 
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The point where the strings meet moves upward at the unknown speed v. What must be the component of this velocity in a direction parallel to one of the sloping strings?
 
A small correction to the problem the final answer is u/cosθ. It's very weird.

I din't get how it not being transversal effects this relation, clearly. If I suppose manage to stop time, after recording the instantaneous speeds of both the strings(Since they are at the same angle and move with the same velocity, I will assume it to be u). They both will move with u in their respective directions, and their vertical components will add up, and result in 2ucosθ. And also, if I take the angle approaching 90. The final answer yields in the velocity of it going upward with a velocity tending to infinity, which is not true. And at 90, it should be zero in reality, which the equation I got perfectly relates whereas the answer yields it as infinity, which by any standards is wrong.
 
With your assumptions, the strings would be moving apart, which does not happen. I suggest you follow the steps proposed in my earlier post. When the strings are near horizontal, a small change in the string length will result in a large change in the height. This is why the result goes to infinity.
 
It yielded me the right answer, sir u/cosθ. Thank you.
It was just a doubt in my mind why my assumption failed over there. I understood it now.
 
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