Why does ψ have a ghost number of -1 in BRST symmetry?

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Discussion Overview

The discussion revolves around the ghost number associated with the field ψ in the context of BRST symmetry, exploring the implications of ghost numbers in the action and the BRST operator. Participants delve into the theoretical aspects of ghost numbers, their conservation, and the role of the BRST operator.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant presents the action in BRST symmetry and questions why ψ has a ghost number of -1.
  • Another participant asserts that ghost number conservation implies that since the action has ghost number zero and the BRST operator s has ghost number +1, ψ must have ghost number -1.
  • A participant expresses confusion about why the s operator has ghost number +1, questioning if it acts as a "charge" of BRST symmetry.
  • Another participant suggests that the s operator may function as a "ladder" operator for ghost number.
  • It is noted that the s operator represents (anti)commutation with the BRST charge, which carries ghost number +1, thus raising the ghost number by +1 when acting with s.
  • A participant mentions that conservation of ghost number is not fundamental and discusses the possibility of using ψ with different ghost numbers, which could break ghost number conservation.
  • One participant queries the relationship [Q,Φ] and how it relates to the s operator being a "ladder" operator of ghost number.
  • Another participant introduces the ghost number operator N and compares its commutation relations to those of a harmonic oscillator.
  • Questions arise about the justification for the commutation relation [N,Q]=+Q and how it leads to the conclusion that the ghost number of s is +1.
  • A participant suggests consulting Srednicki's text for further clarification.
  • One participant reflects on their understanding, proposing that the full BRST transformation involves a fermionic variable θ with a ghost number of -1, leading to the conclusion that s has ghost number +1.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the ghost number of the s operator and its implications. There is no consensus on the nature of ghost number conservation or the role of the s operator, indicating ongoing debate and exploration of these concepts.

Contextual Notes

Some participants' claims depend on specific interpretations of ghost number conservation and the definitions of operators involved, which remain unresolved in the discussion.

ndung200790
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In BRST symmetry the action is

Inew=I0[[itex]\phi[/itex]]+s[itex]\psi[/itex][[itex]\phi[/itex],[itex]\omega[/itex],[itex]\varpi[/itex],h].
Where ω and [itex]\varpi[/itex] is ghost and anti ghost.
If we expand I in series of terms In that satisfy sIn=0(s is BRST operator(Slavnov operator)).
We introduce Hodge operator t=[itex]\varpi[/itex][itex]\delta[/itex]/[itex]\delta[/itex]h.Then
ψ=-∑tIn/n.
They conclude that ψ has ghost number is -1,but I do not understand why?
 
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It follows from your first line. Ghost number is conserved (by construction), the action has ghost number zero, the BRST operator s has ghost number +1, and so ψ must have ghost number -1.
 
I do not understand why s operator has ghost number 1?Is it(s operator) being the ''charge'' of BRST symmetry?
 
Or is s operator being a ''ladder'' operator of ghost number?
 
s represents (anti)commutation with the BRST charge, which carries ghost number +1. So acting with s raises ghost number by +1.

Conservation of ghost number is not a fundamental principle, and you could image using a ψ that includes terms of different ghost number (thus breaking ghost number conservation). It's just that it's more convenient to have ghost number conservation as an additional tool to restrict possible counterterms.
 
Is it the relation:

[Q,[itex]\Phi[/itex]][itex]_{\pm}[/itex]=is[itex]\Phi[/itex]?Then how can we see s being ''ladder'' operator of ghost number?
 
Let N = ghost number operator.

[N,Q]=+Q
[N,ψ]=-ψ

Compare the harmonic oscillator, N=a+a:

[N,a+]=+a+
[N,a]=-a
 
Why we know [N,Q]=+Q?And why by this we know ghost number of s =+1?
 
Sorry, I can't help any more. I suggest taking a look at Srednicki's text.
 
  • #10
Thank very much for your kind helping.
At the moment,I have a new look: the full BRST transformation is θs,where θ is fermionic variable,I think the ghost number of θ is -1(?).Because of BRST symmetry θs has ghost number 0(?) then s has ghost number +1.
Please consider my question again.
 

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