Why does RNA Polymerase always move toward the 5' end of the

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DNA transcription occurs in a specific direction, with nucleotides being added exclusively to the 3' end of the growing mRNA strand. This process is driven by the thermodynamic stability provided by the formation of stronger bonds when the 3' hydroxyl (-OH) of the growing strand interacts with the 5' phosphate of incoming nucleotides. If transcription were to occur towards the 3' end of the template strand, it would lead to potential loss of the 5' phosphate groups, which are crucial for maintaining the integrity of the RNA strand. The weak binding of pyrophosphate groups, which are released during nucleotide addition, could result in halted synthesis if these groups were lost. In contrast, the current mechanism allows for a continuous supply of nucleotides, mitigating any issues related to the loss of pyrophosphate. This understanding emphasizes the importance of directionality in transcription for efficient and stable RNA synthesis.
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DNA strand (template strand) it is transcribing? Why couldn't it move toward the 3' end? Please explain with as much clarification as possible.
I understand the 5' end is the phosphate group end of a nucleotide, and 3' end is the hydroxyl (-OH) end.
I also know that nucleotides are only added to the 3' end of the growing mRNA, but I am confused about why this is, at the molecular level (that the only way to totally understand, isn't it?)
please explain with as much clarification/detail possible, i really need to get this.
thanks alot
 
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My guess is that, if growth were to occur from the 5' end of the primer (i.e. toward the 3' end of the template), the cell would have problems with loss of the 5' phosphate groups. The 5' phosphate is important because the loss of pyrophosphate is the thermodynamic driving force behind DNA/RNA synthesis. The bond is fairly weak, so replacing the pyrophosphate group with the 3'OH of a nucleic acid strand forms a stronger bond and is energetically favorable.

Because the pyrophosphate group is weakly bound, it can sometimes come off due to the thermal energy in the cell. Thus, in an RNA that is transcribed by adding nucleotides to the 5' end, loss of the 5' phosphate would halt synthesis until a repair enzyme could phosphorylate the 5' end again. In contrast, in normal transcription, the transcribed RNA does not have this problem. The pyrophosphate groups are on the nucleotides and loss of these pyrophosphate groups is not a problem because the cell has a large pool of nucleotides that is constantly being replenished.
 
Ygggdrasil said:
My guess is that, if growth were to occur from the 5' end of the primer (i.e. toward the 3' end of the template), the cell would have problems with loss of the 5' phosphate groups. The 5' phosphate is important because the loss of pyrophosphate is the thermodynamic driving force behind DNA/RNA synthesis. The bond is fairly weak, so replacing the pyrophosphate group with the 3'OH of a nucleic acid strand forms a stronger bond and is energetically favorable.

Because the pyrophosphate group is weakly bound, it can sometimes come off due to the thermal energy in the cell. Thus, in an RNA that is transcribed by adding nucleotides to the 5' end, loss of the 5' phosphate would halt synthesis until a repair enzyme could phosphorylate the 5' end again. In contrast, in normal transcription, the transcribed RNA does not have this problem. The pyrophosphate groups are on the nucleotides and loss of these pyrophosphate groups is not a problem because the cell has a large pool of nucleotides that is constantly being replenished.
WOW,
I like this explanation.
 
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