Why does the 30Ns vector get flipped in the Two Dimensional Impulse Problem?

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In the discussion about the Two Dimensional Impulse Problem, a 5.0 kg object moving north at 4.0 m/s experiences a 30 Ns impulse at a 45-degree angle north of west. The main confusion arises from the representation of the 30 Ns vector, which appears reversed in the answer key, leading to a different resultant angle. Participants emphasize the need for clarity on how the vectors were drawn and the interpretation of their directions. The solution process involves using the cosine and sine laws to find the resultant vector and angle. Understanding the correct orientation of the impulse vector is crucial for solving the problem accurately.
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Homework Statement



an object with a mass of 5.0 kg is moving 4.0m/s north when an impulse of 30Ns 45 deg N of W is applied to it. what is its new velocity?

Homework Equations

The Attempt at a Solution



I understand the process until solving for the angle. Why does the 30Ns vector get flipped?[/B]
 
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rusty711 said:
I understand the process until solving for the angle. Why does the 30Ns vector get flipped?
We can't tell what's puzzling you unless you post the actual steps in the working and indicate what you consider to be the flip.
 
haruspex said:
We can't tell what's puzzling you unless you post the actual steps in the working and indicate what you consider to be the flip.

I drew the two vectors how they were given and solved for the resultant and the angle using cos law and sine law. But, in the answer key, the 30Ns vector was drawn reversed resulting in a different angle. Why is this?
 
rusty711 said:
I drew the two vectors how they were given and solved for the resultant and the angle using cos law and sine law. But, in the answer key, the 30Ns vector was drawn reversed resulting in a different angle. Why is this?
I still can't tell whether it is you or the answer key that has it backwards. Can you describe in words how you interpreted the given direction?
 
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